Two charges + 3.2, × ,{10^{ - 19}},C and - 3.2, × ,{10^{ - 19}},C kept 2.4,mathop Alimits^o

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1. Electric Charges and Fields

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Two charges $ + 3.2\, \times \,{10^{ - 19}}\,C$ and $ - 3.2\, \times \,{10^{ - 19}}\,C$ kept $2.4\,\mathop A\limits^o $ apart forms a dipole. If it is kept in uniform electric field of intensity $4\, \times \,{10^{5\,}}\,volt/m$ then what will be its potential energy in stable equilibrium

A

$ + 3 \times {10^{ - 23\,}}\,J$

B

$ -3 \times {10^{ - 23\,}}\,J$

C

$ -6 \times {10^{ - 23\,}}\,J$

D

$ -2 \times {10^{ - 23\,}}\,J$

Solution

Potential energy of electric dipole

$U=-p E \cos \theta=-(q \times 2 l) E \cos \theta$

$U=-\left(3.2 \times 10^{-19} \times 2.4 \times 10^{-10}\right) 4 \times 10^5 \cos \theta$ $U=-3 \times 10^{-23} J \text { (approx.) }$

Standard 12

Physics

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